(5x^2-3y^2)+(x^2+4y^2)=6x

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Solution for (5x^2-3y^2)+(x^2+4y^2)=6x equation:


Simplifying
(5x2 + -3y2) + (x2 + 4y2) = 6x

Remove parenthesis around (5x2 + -3y2)
5x2 + -3y2 + (x2 + 4y2) = 6x

Remove parenthesis around (x2 + 4y2)
5x2 + -3y2 + x2 + 4y2 = 6x

Reorder the terms:
5x2 + x2 + -3y2 + 4y2 = 6x

Combine like terms: 5x2 + x2 = 6x2
6x2 + -3y2 + 4y2 = 6x

Combine like terms: -3y2 + 4y2 = 1y2
6x2 + 1y2 = 6x

Solving
6x2 + 1y2 = 6x

Solving for variable 'x'.

Reorder the terms:
-6x + 6x2 + 1y2 = 6x + -6x

Combine like terms: 6x + -6x = 0
-6x + 6x2 + 1y2 = 0

The solution to this equation could not be determined.

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